|
|
The Monitor
- If you use red, orange, blue, green or cyan LEDs, go to
Step 3. Otherwise, go to Step 2.
- Change your monochrome circuit to use red, orange, blue, green
or cyan LEDs.
- Count the LEDs that you use.
- Buy LEDs. Base the number of LEDs on two facts...
- The LED brightness specification
- The color sensitivity of the human eye. (For example: If you have red LEDs,
buy twice as many green LEDs and one-third as many blue
LEDs.)
|
- For best color balance...
- 59% of your brightness should come from green LEDs.
- 30% of your brightness should come from red LEDs.
- 11% of your brightness should come from blue LEDs.
- For example, with LEDs of the same brightness, and 10 LEDs total,
use 6--GRN, 3--RED and 1--BLU.
- With fewer LEDs, the circuit is
simpler, but the color balance tends to be less accurate.
- You can balance inaccuracies by adding potentiometers in series
with the LEDs.
- Compensate for brightness differences in the different colors. For example,
your red LEDs might be twice as bright as your green LEDs. You can
compensate by reducing the number of red LEDs.
- Use LEDs that have about the same viewing (dispersion) angle.
- Assure full screen coverage by mounting LEDs at a sufficient distance
from the viewing window.
- Use an adequate diffuser. Make sure that your diffuser doesn't block
too much light.
|

|
- Duplicate your LED driver circuit (power amplifier) once for two-color TV. For
three-color TV, make two copies of your LED driver.
- Connect the LEDs to the new LED drivers.
- Test the set.
Option: Derived Color
Following the instructions above, build a two-color camera and a
three-color monitor. You can build your camera to pick up any two
of the additive primary colors. Just install the proper color filters
over the phototransistors or photodiodes. With a matrix circuit and an
inverter, you will derive the third color. The trick? You
might not have the third color, but you can create its
complement. A bit of electronics turns the complement back into
the "missing" primary color.
- Derive Blue... You want a blue signal, but your camera
only picks up green and red.
- At the monitor, connect a potentiometer
to the red and green LED driver outputs. This potentiometer is
your resistor matrix. Some point on the pot's resistance
element corresponds to yellow, the complement of blue.
- With a transistor, invert the yellow signal, and you have
your blue. The result is as accurate as if it came from a blue
phototransistor.
- You can derive this third color signal at the camera or at
the monitor. For maximum savings in circuitry, derive the signal
at the monitor (LED driver).
- Derive Green... Suppose that you only have red and blue, but want green.
- Connect a potentiometer between the red and blue transistor collectors (or
op amp outputs).
- The red signal is at one end of the potentiometer. The blue signal is at
the other end. With the wiper at the center position, you get a mix of red
and blue, or magenta. This magenta signal is what you want. Center the wiper.
- Run the wiper of the pot to the base of a new transistor (or an op amp
input). With the transistor or op amp, invert the magenta signal. The
inverted signal is your green drive signal.

- Derive Red... Now you want red, but only have green and blue. Cyan is
between
green and blue. With a transistor, invert the cyan signal and you
have your red.

Another way to derive a third color: An inverting mixer.
Inverting mixer. An inverting mixer is an easy way to derive a third color. (See
the schematics above.) For experimental use, use the circuits as-is. The phasing is only
approximate. For better phasing, add level-adjustment pots to the transistor inputs.
- Red. To derive the red signal, use the left
circuit.
- Green. To derive the green signal, use the middle circuit.
- Blue. To derive the blue signal, use the right circuit.
Theory. Each transistor is an inverting phase-splitter. After a 180-degree phase
shift, the input signals mix at the common collector resistor. Neither amplifier has any
voltage gain. Yet each amplifier offers an 11.8-times power gain. You can take the
in-phase signal off the emitter of each transistor. The emitter signal includes the
power gain.
Go to Page:
1
2
Back
|
Article directory
|